最近我们在一个客户的oracle恢复case中发现比特币文件系统勒索加密比较特殊,和大家做一个分享
文件加密后缀名为:.$ILICONE

文件加密特点分析

DUL> dump datafile 5 block 1
Block Header:
block type=0x0b (file header)
block format=0xa2 (oracle 10)
block rdba=0x01400001 (file#=5, block#=1)
scn=0x0000.00000000, seq=1, tail=0x00000b01
block checksum value=0x6e7d=28285, flag=4
File Header:
Db Id=0xe1891cca=3783859402, Db Name=XIFENFEI, Root Dba=0x0
Software vsn=0x0, Compatibility Vsn=0xa200300, File Size=0x3ffffe=4194302 Blocks
File Type=0x3 (data file), File Number=5, Block Size=8192
Tablespace #7 - OA rel_fn:5
DUL> dump datafile 5 block 2
Block Header:
block type=0x63 (unknown)
block format=0x57 (unknown)
block rdba=0xc6538298 (file#=793, block#=1278616)
scn=0xe0ab.fdc4d8d0, seq=225, tail=0xa7b5cab5
block checksum value=0xfaa1=64161, flag=165
corrupted block.
DUL> dump datafile 5 block 3
Block Header:
block type=0x1e (LMT space map block)
block format=0xa2 (oracle 10)
block rdba=0x01400003 (file#=5, block#=3)
scn=0x0000.00246fbe, seq=1, tail=0x6fbe1e01
block checksum value=0xe495=58517, flag=4
DUL> dump datafile 5 block 4
Block Header:
block type=0x83 (unknown)
block format=0xa3 (unknown)
block rdba=0x17e4c9e4 (file#=95, block#=2410980)
scn=0xe3b2.fc505eea, seq=101, tail=0x6e2f1004
block checksum value=0x7f2e=32558, flag=196
corrupted block.
DUL> dump datafile 5 block 5
Block Header:
block type=0x1e (LMT space map block)
block format=0xa2 (oracle 10)
block rdba=0x01400005 (file#=5, block#=5)
scn=0x0000.00264875, seq=1, tail=0x48751e01
block checksum value=0xb25e=45662, flag=4
DUL> dump datafile 5 block 6
Block Header:
block type=0x68 (unknown)
block format=0x35 (unknown)
block rdba=0x7011e0e3 (file#=448, block#=1171683)
scn=0x47bf.9f2df54a, seq=207, tail=0x69ae0a91
block checksum value=0x49f8=18936, flag=174
corrupted block.

通过这里初步分析,确认加密是间隔方式加密,在数据库中表现明显的是每相隔8k进行加密,而且这里是偶数block被加密
确认加密文件结束位置

DUL> dump datafile 5 block 962818 header
Block Header:
block type=0x4d (unknown)
block format=0xde (unknown)
block rdba=0x0bab780d (file#=46, block#=2848781)
scn=0x056b.2c695f6b, seq=223, tail=0x2399e0cb
block checksum value=0x9706=38662, flag=212
corrupted block.
DUL> dump datafile 5 block 962820 header
Block Header:
block type=0x00 (blank block)
block format=0xa2 (oracle 10)
block rdba=0x014eb104 (file#=5, block#=962820)
scn=0x0000.00000000, seq=1, tail=0x00000001
block checksum value=0x174a=5962, flag=5

通过这里可以发现,对于一个32G的文件,一直被加密到block 962818,也就是7.34G(962818*8k),这里间隔加密,而且加密深度特别深,在以往的比特币文件系统加密中比较少见.
再次提醒
1. 不要把数据库暴露在外网
2. 相对linux而言,win更容易受到黑客的攻击
3. 数据库一定要做好备份,条件允许的情况下,配置数据实时同步到其他机器还是有必要的