procmap是用来显示进程地址空间，通过这个命令找出来的“read/write”表示为进程的私有内存,如果对应到oracle 进程的LOCAL中来,也就是对应了是oracle 会话进程占用的操作系统内存,和sga与pga无关，即ORACLE数据库进程占用的额外的系统内存,在计算oracle数据库消耗内存的时候，要考虑sga+pga+process占用的内存
procmap命令使用
$procmap 7931354
7931354 : oracleccicdx (LOCAL=NO)
100000000 95504K read/exec oracle
110000035 2399K read/write oracle
9fffffff0000000 51K read/exec /usr/ccs/bin/usla64
9fffffff000cfe2 0K read/write /usr/ccs/bin/usla64
900000000b05930 2K read/exec /usr/lib/libC.a[shr3_64.o]
9001000a0122930 0K read/write /usr/lib/libC.a[shr3_64.o]
900000000ae6b00 118K read/exec /usr/lib/libC.a[shrcore_64.o]
9001000a030a100 12K read/write /usr/lib/libC.a[shrcore_64.o]
900000000ac8000 118K read/exec /usr/lib/libC.a[ansicore_64.o]
9001000a0300e00 36K read/write /usr/lib/libC.a[ansicore_64.o]
900000000411468 0K read/exec /usr/lib/libicudata.a[shr_64.o]
9001000a0121468 0K read/write /usr/lib/libicudata.a[shr_64.o]
90000000040f738 2K read/exec /usr/lib/libC.a[shr2_64.o]
9001000a0314738 0K read/write /usr/lib/libC.a[shr2_64.o]
9000000008dd800 1699K read/exec /usr/lib/libC.a[ansi_64.o]
9001000a0315a00 277K read/write /usr/lib/libC.a[ansi_64.o]
9000000008bab00 135K read/exec /usr/lib/libC.a[shr_64.o]
9001000a030eb00 19K read/write /usr/lib/libC.a[shr_64.o]
900000000708180 1732K read/exec /usr/lib/libicuuc.a[shr_64.o]
9001000a035cdac 180K read/write /usr/lib/libicuuc.a[shr_64.o]
900000000493d80 2510K read/exec /usr/lib/libicui18n.a[shr_64.o]
9001000a038a148 270K read/write /usr/lib/libicui18n.a[shr_64.o]
900000000473200 91K read/exec /usr/lib/libsrc.a[shr_64.o]
9001000a01127a8 55K read/write /usr/lib/libsrc.a[shr_64.o]
90000000045a300 98K read/exec /usr/lib/libcorcfg.a[shr_64.o]
9001000a04147c8 18K read/write /usr/lib/libcorcfg.a[shr_64.o]
900000000b16200 750K read/exec /usr/lib/liblvm.a[shr_64.o]
9001000a03dd028 219K read/write /usr/lib/liblvm.a[shr_64.o]
900000000444f00 82K read/exec /usr/lib/libcfg.a[shr_64.o]
9001000a03d58f0 26K read/write /usr/lib/libcfg.a[shr_64.o]
90000000040e3a0 2K read/exec /usr/lib/libcrypt.a[shr_64.o]
9001000a0106948 0K read/write /usr/lib/libcrypt.a[shr_64.o]
90000001615d860 5K read/exec /usr/lib/libc.a[aio_64.o]
9001000a3aed568 0K read/write /usr/lib/libc.a[aio_64.o]
9000000003efc00 120K read/exec /usr/lib/libodm.a[shr_64.o]
9001000a0107cc8 40K read/write /usr/lib/libodm.a[shr_64.o]
900000000bd2c80 147K read/exec /usr/lib/libperfstat.a[shr_64.o]
9001000a041a960 14K read/write /usr/lib/libperfstat.a[shr_64.o]
9000000017d7000 0K read/exec /usr/lib/libdl.a[shr_64.o]
9001000a0517000 0K read/write /usr/lib/libdl.a[shr_64.o]
9000000158ed100 8636K read/exec /oracle/product/db10gr2/lib/libjox10.a[shr.o]
8001000a0000b78 587K read/write /oracle/product/db10gr2/lib/libjox10.a[shr.o]
900000000a87000 257K read/exec /usr/lib/libpthreads.a[shr_xpg5_64.o]
9001000a0274000 559K read/write /usr/lib/libpthreads.a[shr_xpg5_64.o]
900000000000800 4025K read/exec /usr/lib/libc.a[shr_64.o]
9001000a0000020 1047K read/write /usr/lib/libc.a[shr_64.o]
Total 121863K
简化命令，统计私有内存,procmap 7931354|grep “read/write” |awk -F ” ” ‘{print $2}’,通过相关计算的出来,在当前的操作系统和数据库版本中，一个LOCAL=NO进程占用系统内存为:5758KB
补充说明
1.操作系统版本
$oslevel -r 6100-06
2.数据库版本
SQL> select * from v$version; BANNER ---------------------------------------------------------------- Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi PL/SQL Release 10.2.0.4.0 - Production CORE 10.2.0.4.0 Production TNS for IBM/AIX RISC System/6000: Version 10.2.0.4.0 - Productio NLSRTL Version 10.2.0.4.0 - Production
3.通过跟踪多个LOCAL=NO进程,发现类似进程占用的系统内存相同,估算给系统oracle进程占用的内存，可以通过该值进行大概估算
4.确认ORACLE使用的内存量不是以往认识的sga+pga，实际上应该是sga+pga+所有oracle进程占用
5.在linux中使用pmap来查看
